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Laketon, Indiana

Laketon, Indiana
Location of Laketon in Wabash County, Indiana.
Location of Laketon in Wabash County, Indiana.
Coordinates: 40°58′50″N 85°50′22″W / 40.98056°N 85.83944°W / 40.98056; -85.83944
CountryUnited States
StateIndiana
CountyWabash
TownshipPleasant
Area
  Total
1.22 sq mi (3.15 km2)
  Land1.05 sq mi (2.73 km2)
  Water0.16 sq mi (0.42 km2)
Elevation758 ft (231 m)
Population
 (2020)
  Total
606
  Density574.9/sq mi (221.97/km2)
Time zoneUTC-5 (Eastern (EST))
  Summer (DST)UTC-4 (EDT)
ZIP code
46943
FIPS code18-41562[3]
GNIS feature ID2629856[2]

Laketon is an unincorporated census-designated place in Pleasant Township, Wabash County, in the U.S. state of Indiana.[2] As of the 2020 census, Laketon had a population of 606.[4]

History

[edit]

Laketon was laid out in 1836.[5] A post office was established at Laketon in 1838, and remained in operation until it was discontinued in 2010.[6]

Demographics

[edit]
Historical population
CensusPop.Note
2020606
U.S. Decennial Census[7]

References

[edit]
  1. "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
  2. 1 2 3 U.S. Geological Survey Geographic Names Information System: Laketon, Indiana
  3. "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
  4. "2020 Decennial Census Redistricting Data (Public Law 94-171)". United States Census Bureau. 2021. Retrieved March 11, 2026.
  5. Woodward, Ron. Laketon. Retrieved May 10, 2018.
  6. Brubaker, Ruth M. (1979). The History of Pleasant Township Schools 1835-1962. Retrieved May 10, 2018.
  7. "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.